Question

if 2^x = 4x2^y and 9x3^x = 3^-y. find X and y
just say the ans​

Answer 1

x = 0 and y = -2

$= > {2}^{x} = 4 \times {2}^{y} \\ = > \frac{ {2}^{x} }{ {2}^{y} } = 4 \\ = > {2}^{x - y} = 4 \\ = > {2}^{x - y} = {2}^{2} \\ = > x - y = 2..................(1) \\ \\ 9 \times {3}^{x} = {3}^{ - y} \\ = > {3}^{2} \times {3}^{x} = {3}^{ - y} \\ = > {3}^{x + 2} = - y \\ = > x + 2 = - y \\ = > x + y = - 2...............(2) \\ solving \: eq \: (1) \: and \: (2) \\ x - y = 2 \\ x + y = - 2 \\ ................... \\ - 2y = 4 \\ y = - 2 \\ putting \: y \: in \: eq1 \\ x = - 2 + 2 \\ x = 0$