Question

If √(2^x) = 64, then (x² - 80)/16 = ?

Answer 1

Answer: 4

Step-by-step explanation:

$\sqrt{2^{x} } =64\\2^{\frac{x}{2} } =64\\2^{\frac{x}{2} } = 2^{6}\\\frac{x}{2} =6\\x=12$

$\frac{x^{2} -80}{16} =\frac{144-80}{16} =4$