If 2|x| = \- 8| + |x + 8| then the complete set of
values of x are
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Step-by-step explanation:
Given x2−x+a−3<0
For at least one negative value of x.
The coefficient of x2 is positive. The expression on the left-hand side must be positive at infinitely many points. It can be negative at least one point if the smaller root were negative.
21−13−4a<0
⇒13−4a>1
⇒13−4a>1
⇒4a>12
⇒a<3
⇒a∈(−∞,3)
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