Math, asked by poonamthapa589, 7 months ago

if 2 X + K is a factor of the polynomial 8 x cube + 4 K X square + 3 X + K - 1 find the value of k​

Answers

Answered by spandhana238
5

Answer:

given, 2x + K is a factor of the polynomial

8x^3 + 4kx^2+ 3x + K - 1

so, 2x+k=0

2x = -k

x = -k/2

substitute x = -k/2 in the given polynomial

8(-k/2)^3 + 4k(-k/2)^2 + 3(-k/2) + k - 1 = 0

-8k^3/8 + 4k^3/4 - 3k/2 + k - 1 = 0

-k^3 + k^3 -3k/2 + k - 1 = 0

-3k + 2k - 2 = 0

2

-3k + 2k -2 =0

k = -2

Answered by tanishkavi
0

Answer:

-2

Step-by-step explanation:

2x+k=0

=-k/2

8(-k/2)3+4k(-k/2)2+k-1

-3k+2k-1=0

-1-1=k

k=-2

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