if 2 X + K is a factor of the polynomial 8 x cube + 4 K X square + 3 X + K - 1 find the value of k
Answers
Answered by
5
Answer:
given, 2x + K is a factor of the polynomial
8x^3 + 4kx^2+ 3x + K - 1
so, 2x+k=0
2x = -k
x = -k/2
substitute x = -k/2 in the given polynomial
8(-k/2)^3 + 4k(-k/2)^2 + 3(-k/2) + k - 1 = 0
-8k^3/8 + 4k^3/4 - 3k/2 + k - 1 = 0
-k^3 + k^3 -3k/2 + k - 1 = 0
-3k + 2k - 2 = 0
2
-3k + 2k -2 =0
k = -2
Answered by
0
Answer:
-2
Step-by-step explanation:
2x+k=0
=-k/2
8(-k/2)3+4k(-k/2)2+k-1
-3k+2k-1=0
-1-1=k
k=-2
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