Question

If 2(x - y)2 = 116 and xy = 4
and xy = 24, find the value of x2 + y2.


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Answer 1

Answer:

2(x^2+y^2-2xy)=116

x^2+y^2-2xy=58

x^2+y^2-2×24=58

x^2+y^2=58+48

x^2+y^2=106

Answer 2

Answer:

Step-by-step explanation:

Here the given equation is 2(x-y)²=116

And xy= 24

Now 2(x-y)²=116

Or. x²-2xy+y²=116/2

Or. x²+y²-2(24)=58

Or. x²+y²-48=58

Therefore x²+y²=48+58

=106

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