if 2^x+y = 2^x-y = √8 find the value of y
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2^(x + y) = 2^(x - y)
(2^x)(2^y) = (2^x)(2^-y)
2^y = 2^-y
2^y = 1/2^y
2^y * 2^y = 1
2^2y = 1
Value of y should be “0” so that 2^0 = 1
(2^x)(2^y) = (2^x)(2^-y)
2^y = 2^-y
2^y = 1/2^y
2^y * 2^y = 1
2^2y = 1
Value of y should be “0” so that 2^0 = 1
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