Question

If |
2 −y
1 x
| = 16 and |
3 2
y x
| = 3, then form two simultaneous equations from the given

determinants and solve.​

Answer 1

Step-by-step explanation:

question not cleared

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Answer 2

Answer:

x=5, y=6

explaination

in the first determinent we get

2×+y=16 is eq 1

in the second determinent we get

3×-2y =3 is eq 2

we multiple the eq 1 with 2

we get

4×+2y =32:

the -2y + 2y get cancle

we have 7× =35

x=5

sub x =5 in eq we get

10 +y = 16 y= 16-10=6