if 2 Y - 3 divide 6 Y minus 5 equal 1 upon 3 then the value of Y
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2Y - 3/6Y - 5 = 1/3
Cross-multiplying the equation, we get,
3(2Y - 3) = 1(6Y - 5)
6Y - 9 = 6Y - 5
6Y + 6Y = -5 + 9
12Y = 4
Y = 4/12
Y = 1/3
Hence, the required value of Y is 1/3
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