Question

If 2 zeros of a polynomial x3-3x2+2 are 1+√3 and 1-√3 respectively. Then find the third zero

Answer 1

Answer:

Step-by-step explanation: first ,find sum and product of given zeroes

α+β=1+√3+1-√3. And αβ=1²-√3²

Second,form a polynomial with the sum and product of given zeroes

X²-2x-2 [ x^2-(α+β)x+(αβ)]

Third, Divide x³-3x²+2 by x²-2x-2

Fourth,on dividing we get a quotient ,then factorise the obtained quotient

Here quotient is x-1 ,by factorising it we get x=1

Hence, third zero is 1