Question

if 2 zeros of polynomial x^4-6x^3-26x^2+138x-35 are 2+√3 and 2-√3, find other zeros

Answer 1

Answer:

Step-by-step explanation:

x=2+√3

x-2-√3=0......2

x=2-√3

x-2+√3=0 .....1

so 1x2==>x²-4x+1 ......this is the a factor of the given polynomial

x^4-6x^3-26x^2+138x-35/x²-4x+1 = another factor

that factor is x²-2x-35

split the middle term

x²-7x+5x-35=0

x(x-7)+5 (x-7)=0

(X-7)(x+5)=0

x=7 or -5

hope it helps

Answer 2

x=2+√3

x-2-√3=0......2

x=2-√3

x-2+√3=0 .....1

so 1x2==>x²-4x+1 ......this is the a factor of the given polynomial

x^4-6x^3-26x^2+138x-35/x²-4x+1 = another factor

that factor is x²-2x-35

split the middle term

x²-7x+5x-35=0

x(x-7)+5 (x-7)=0

(X-7)(x+5)=0

X=7 or -5