If 2 zeros of the polynomial x⁴- 6x³-26x²+138-35 are 2+√3 and 2-√3,find other zeros.
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Answer:
since 2+√3 is zero
x-(2+√3) is a factor of polynomial
since 2-√3 is a zero
x-(2-√3) is a factor of polynomial
this means (x-2-√3)(x-2+√3)
(x-2)^2-(√3)^2
x^2-4x+4-3
x^2-4x+1
x^2-4x+1 is a factor of x^4-6x^3-26x^2+138x-35
so we divide them with algorithm method
we get answer x^2-2x-35
x^2-7x+5x-35
X(x-7)+5(x-7)
(X+5)(x-7)
The other zeroes are
-5and 7
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