If 20.0 ml of 0.500 M KOH is titrated with 0.250 M HNO3, how many millilitres of nitric acid are required to neutralize the base? show formulas and calculations.
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molarity and volume of KOH is 0.5M,20ml..
M1=0.5M. V1=20ml
molarity of nitric acid is 0.25M,volume is ??
M2=0.25M. V2=?
KOH+HNO3--------^ KNO3+H2O
M1V1=M2V2
0.5*20=O.25*V2
V2=40ml
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