.If (20 − 3) = cot(5 − 20) then find the value of and hence evaluate sin ∙ sectan−cos ∙cot)
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Answer:
Given tan(20−3α)=cot(5α−20)
⟹tan(20−3α)=tan(90−5α+20)
⟹tan(20−3α)=tan(110−5α)
⟹20−3α=110−5α
⟹5α−3α=110−20
⟹2α=90
⟹α=
2
90
=45
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