Math, asked by titanium07info, 10 months ago

If 20-5x<5(x+8), find the smallest value of x when (1) x is an integer (2) x is a whole number (3) x is a natural number

Answers

Answered by chennailins
4

Answer:

Natural nos. start from 1

whole Nos. start from 0

Step-by-step explanation:

1. when x is an integer,

x can also be a negative no.

smallest value of x can be any negative no.

2. when x is a whole no. , the smallest available whole no. is 0

so, x= 0

3. when x is a natural no.

smallest natural no. is 1,

so, x = 1

Answered by Anonymous
29

Answer:

\boxed{\red{\text{HERE IS THE ANSWER}}}

20 - 5x &lt; 5(x + 8) \\ 20 - 5x &lt; 5x + 40 \\ 20 - 40 &lt; 5x + 5x \\  - 20 &lt; 10x \\  - 2 &lt; x

1. -1

2. 0

3. 1

PLEASE MARK ME AS BRAINLIEST IF THE ANSWER IS CORRECT

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