Question

if 20 cm³ gas at 1 ATM is expanded 50 cm ³ of constant . then what is the final pressure?​

Answer 1

Answer:

20 cm

Explanation:

Answer 2

Answer:

Final pressure = 0.4 atm

Explanation:

Boyle's Law states that at constant temperature, the pressure (P) of a gas varies inversely with its volume (V).

$\rm P \propto \dfrac{1}{V}$

i.e. PV = Constant

$\therefore$ $\rm P_1 V_1 = P_2 V_2$

According to the question,

$\rm P_1$ = 1 atm

$\rm V_1$ = 20 cm³

$\rm V_2$ = 50 cm³

$\rm \implies 1 \times 20 = P_2 \times 50 \\\\ \rm \implies P_2 = \dfrac{20}{50} \\\\ \rm \implies P_2 = 0.4 \ atm$

So, the final pressure = 0.4 atm