Question

If 20 g NaOH and 36.5 g HCI are added with
360 g water; then % by weight HCI present in the
resulting mixture is
(1) 4.38
(2) 3.23
(3) 6.46
(4) 8.76

OPTION (1) IS CORRECT
PLEASE SOLVE IT​

Answer 1

Answer:

(1)

Explanation:

As we know,

% purity = Weight of solute in gm  * 100% / weight of solvent in gm

here, weight of solute i.e HCL = 36.5g  

weight of solvent ie total weight after mixing = ( 20+36.5+360) =416.5g

now, % purity of HCL =  36.5*100%/416.5

                                   = 4.38

so option (1) is correct.