Question

If 20 g of a gas at 1 atmosphere pressure is cooled from 273°C to 0°C at constant volume its pressure would become

Answer 1

Answer:

Given,

T1=273∘ or 546.15 K

P1=1 atm

T2=0∘C or 273.15 K

P2=?

∴T1P1=T2P2

∴P2=T1P1×T2=546.151×273.15

         =21atm or 5.05×104Nm−2

Explanation:

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