if 20 g of helium defuses through a hole in 10 seconds then calculate mass of SO2 gas refusing through the same volume 15 seconds
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Answer:
The rate of diffusion is volume diffused per unit time and is inversely proportional to the square root of molar mass.
r
′
r
=
V
′
t
Vt
′
=
M
M
′
Here, r, V, t, and M are the rate of diffusion, the volume diffused, the time taken for diffusion and the molar mass of SO
2
and r', V', t' and M' are the rate of diffusion, the volume diffused, the time is taken for diffusion and the molar mass of O
2
respectively.
Substitute values in the above equation
V
′
×60
20×30
=
64
32
V
′
=14.14 L.
Hence, a volume of O
2
diffused under similar conditions in 30 seconds will be 14.14 L.
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