Question

if 20 gm of CaCo3 reacts with 20 gm of hcl how much co2 is formed

Answer 1

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Answer 2

Explanation:

Let, the volume of O

3

=x mL.

Volume of O

2

present =(600−x) mL

22400 mL of O

3

and O

2

at STP will weight 48 g and 32 g respectively.

The weight of x mL of O

3

=

22400

x×48

g.

The weight of (600−x) mL of O

2

=

22400

(600−x)

×32.

Total weight of ozonised O

2

(600mL) =

22400

48x

+

22400

(600−x)×32

=1.0.

∴x=200 mL