Question

If 20 gram of calcium carbonate top treated with 24 10 gram of hydrochloric acid how many grams of carbon dioxide can be produced according to reaction

Answer 1

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CaCO3(s)(1mole , 100g) + (73g , 2mol) 2HCl(aq.) →CaCl 2 (aq.)+H2O(l) + (44g , 1mol)CO 2 (g)

Let CaCO3(s) be completely consumed in the reaction.

∵100gCaCO3 give 44gCO2

∴20gCaCO3 will give 44/100 ×20gCO2 =8.8gCO2

Let HCl be completely consumed.

∵ 73 g HCl give 44 g CO2

∴ 20 gHCl will give 44/73 × 20gCO2 = 12.054gCO2

Since, CaCO3 gives least amount of product CO2 , hence CaCO3 is limiting reactant. Amount of CO2 formed will 8.8g.

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