Question

if 20 gram of water at 60 degree celsius is mixed with 60 gram of water at 20 degree Celsius the resultant temperature is​

Answer 1

the final temprature is thirty degree celcius...

sorry for taking too much time actually i had done a mistake in writing the numerical values

Answer 2

Answer:

Final temperature is 30°C

Explanation:

Given,

$20gram \: water \: at \: {60}^{o} celcius$

add with

$60gram \: water \: at \: {20}^{o} celcius$

Heat lost by 60°C water = Heat gain by 20°C water.

Let final temperature be T°C.

$20 \times s \times (60 - T) = 6 \times (T - 20)$

$60 - T = 3T - 60$

$4T = 120$

$T = \frac{120}{4}$

$T = 30$

Final temperature is 30°C