if 20 grams of water at 20 degree celsius is supplied 20 calories of heat energy than the temperature of water is
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Answer:
Q = m × Cp × Change in Temp
Q = heat supplied in calories = 60 cal (given)
m = mass of water in gram = 15 grams (given)
Cp = Specific heat capacity of water at constant pressure (cal/gK) = 1 cal/gK (known)
Thus
60 = 15 × 1 × Change in Temp
Thus Change in Temp = 60÷15
Change in Temp = 4 K
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