Physics, asked by dony9713, 11 months ago

If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is

Answers

Answered by itzJitesh
26

Answer:

weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is

[A]. 7.30

[B]. 7.35

[C].

7.40 @

[D]. 7.45

[E]. none of these.

Answer: Option C

Explanation:

80 MM 0 0 0

40 2 10 10

20 8 40 50

10 6 30 80

4.75 4 20 100

2.36 0 0 100

1.18 0 0 100

600 0 0 100

300 0 0 100

150 0 0 100

TOTAL 740.

FINENESS MODULUS = 740/100 = 7.4.

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