if 20 kg of water from 10 degree Celsius to 35 degree celsius using an immersion heater at 8000 Watts assume that 80% of power input is used to heat the water the time required to heat a specific heat capacity of water 4200 joules per kg
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The time required to heat the water is 328.13 seconds.
Explanation:
Temperature change "ΔT" = (35 - 10)°C = 25°C
Mass of water "m" =20 kg
Power "P" =8000 W
Power output = 8000×80/100
= 6400 W
Capacity of water "c"=4200 J/kg °C
Q = (25×20×4200)J
Let time taken be "t" seconds.
25×20×4200/t = 6400
t = 25×20×4200/6400
t = 328.13 seconds = 5.46 minutes
Hence the time required to heat the water is 328.13 seconds
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An immersion heater rated 1.5 kW is used to heat 10 kg of water. Calculate the time taken in raising the temperature of the water by 32°C. Specific heat capacity of water is 4200 J/kg °C.?
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