Question

If 20 litre SO2 reacts completely with 40
litre O2 to form SO, according to the
following equation. At the end of
reaction the volume of the substance is
2SO2+O2→2SO3

(a) 20 L (b) 30 L (c) 40 L (d) 50 L​

Answer 1

Answer:

Explanation:

2SO2(g) + O2(g) → 2SO3(g)

Here, mole ratio between SO3 and O2 = 2 : 1. Assume that the reaction occurs at STP condition where, 1 mole of any gas has the volume of 22.4 L. Thus, 30 dm3 of O2 (1 dm3 = 1 L) = 30 L of O2 = 30 L/22.4 L x 1 mole = 1.34 moles of O2. Stoichiometrically, 1.34 moles of O2 upon reacted with SO2 produce 2/1 x 1.34 moles of SO3 or 2.68 moles of SO3.

So, the volume of SO3 generated will be (2.68 moles/1 mole) x 22.4 L = 60.03 L SO3.

Answer 2

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