Math, asked by palshivam214, 1 year ago

if 20 men can build a 112m long wall in 6 days. what will be the length of a similar wall that can be built by 25 men in 3 days.

Answers

Answered by devadakshan
62
20 men × 6 days = 112m long
120 = 112m long
1 men 1 day= 112/120
1 men 1 day= 0.933 m long (approx)

25 men × 3 days
=> (25×3) × 0.933
=> 75 × 0.933
=> 69.975 m long

The length of wall built using 25 men in 6 days is => 70m long

devadakshan: Make it brainlyliest if it helps u
Answered by rohitkumargupta
55
HELLO DEAR,


LET THE REQUIRED LENGTH BE x METERS

 MORE MEN, More Length Built     (DIRECT PROPORTION) 

LESS DAYS, LESS LENGTH BUILT    

 (DIRECT PROPORTION)


MEN, 20 : 25}::
DAYS ,6 : 3}:: 112 : x


=> (20 x 6 x X)=(25 x 3 x 112) 

=> x =

Hence, the required length is m.

x =  \frac{25 \times 3 \times 112}{20 \times 6}  \\  =  > x =  \frac{75 \times 112}{120}  \\  =  >  \frac{8400}{120}  \\  =  > x = 70meter
I HOPE ITS HELP YOU DEAR,
THANKS


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