If 20 ml of 1.0 M CaCl2 and 60 ml of 0.2 M CaCl2 are mixed, what will be the molarity of the final solution?
Answers
Answered by
0
Answer:
0.4 M CaCl2
Explanation:
We know that,
S1×V1 + S2× V2 = S×V
Here, S1=1M, V1=20 ml, S2=0.2M, V2=60ml
V=V1+V2= 20+60= 80ml
> S=( S1×V1 + S2× V2) / V
> S= ( 1×20 + 0.2×60) / 80
> S= 0.4 M CaCl2
Similar questions