Question

if 20 mL of NaOH solution is found to be neutralised
completely by 10 mL of HCl solution then amount of same
HCl solution required to neutralize 40 mL of NaOH solution (same concentration) is ??​

Answer 1

Answer:

20 ml

Explanation:

Since concentration is same the amt. of HCl reqd is twice as previous.

Answer 2

Answer:

To fully neutralize $40ml$ $NaOH$, the volume of $HCl$ required is $20ml$.

Explanation:

Given,

The $NaOH$ solution's volume = $20ml$

To neutralize $20ml$ $NaOH$ solution, the volume of $HCl$ required = $10ml$

The volume of another solution of $NaOH$ = $40ml$

To neutralize another $40ml$ $NaOH$, the volume of $HCl$ required =?

As given,

• $20ml$ $NaOH$ neutralized by = $10ml$ $HCl$

Thus,

• $1ml$ $NaOH$ neutralized by = $\frac{10}{20}ml$ $HCl$

Now,

• $40ml$ $NaOH$ neutralized by = $40\times \frac{10}{20}ml$ $HCl$ = $20ml$ $HCl$.

Hence, to fully neutralize another $40ml$ $NaOH$, the volume of $HCl$ required is $20ml$.