Question

If 20%of a=b and40%of b=c then find 60%(a+b)

Answer 1

60%(a+b)
60%(20+40)
60%100/60
36.6666..%

Answer 2

Let A = 100,

Then, according to question 20% of A = 100×20/100 = 20 i.e., B = 20,

Now again according to question 40% of B = 20×40/100 = 8 i.e., C = 8

Hence, ( A + B )= 100 + 20

= 120

Now, 60% of (A + B) = 120 × 60/100

=72

Now 72/8×100 = 900 i.e., 900% of C
60% of (A + B) = 900% of C
you can prof it by taking number such as A = 60 or any other number
Let's see C = 8, therefore 900% of 8 = 8× 900/100 = 72 it's proved.