Question

if 20 ohm is resistance o coil of galvanometer and 0.1005 is resistance of shunt then resistance of ammeter will be?

Answer 1

Explanation:

shunt resistance and galvanometer resistance are in parallel so resistance of ammeter is shown above in the pic

Answer 2

The resistance of ammeter will be $0.1\Omega$.

Explanation:

To convert galvanometer as ammeter, a shunt resistance need to be connected to galvanometer in  parallel.

Let galvanometer resistance is R and shunt resistance is S and they are in parallel combination, then

$\frac{1}{R_{ameter} } =\frac{1}{R}+\frac{1}{S}$

Given R = 20 ohm and S  = 0.1005 ohm.

substitute these values, we get

$\frac{1}{R_{ameter} } =\frac{1}{20\Omega}+\frac{1}{0.1005\Omega}$

            $= 0.05\Omega + 9.95\Omega$

$R_{ammeter}= \frac{1}{10}= 0.1\Omega$

Thus, the resistance of ammeter will be $0.1\Omega$.

#Learn More:galvanometer resistance.

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