If 20 times of the 20th term of an A.P is equal to 11 times of the 11th term then find the 31st term.
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The 31st term is 0.
Given,
An AP has -
20a₂₀ = 11a₁₁
To Find,
31st term
Solution,
The general term of an AP is given as -
Tₙ = a + (n - 1)d
20a₂₀ = 11a₁₁
20 (a + 19d) = 11 (a + 10d)
20a + 380d = 11a + 110d
9a = - 270d
a = -30d
a₃₁ = a + (31 - 1)d
a₃₁ = a + 30d
As derived above a = -30d
a₃₁ = -30d + 30d
a₃₁ = 0
Thus, we get the 31st term as 0.
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