If 20! were multiplied out, how many consecutive zeros would it have on the right?
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Answer:
Hello mate ^_^
Your answer is 20!
Step-by-step explanation:
1×2×3×4×5
×6×....×10×11
×.......14×15
×........×20
We observe in 20! that there one 4 consecutive zeros to the right i.e
4×5 =20 , 10, 14×15 =210
& 20 give Zeros.
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