Question

If 200 gram of Ba(OH)2 is treated with 20 gram of HCl, how many grams of BaCl2 do we get?

Answer 1

${\bold{\huge{\red{\underline{\green{ANSWER}}}}}}$

EQUATION REQUIRED:

$Ba(OH)_2 + HCl \rightarrow BaCl_2$

now,

If 171 g of ${ Ba(OH)_2 }$ gives 208 g of ${BaCl_2}$

then 200 g of ${Ba(OH)_2}$ gives x g of ${BaCl_2}$

now to find x :

$x = \frac{200 \times 208}{171}$

$x = 243.27 \: g$