Question

If 200 lb of a mixture contain 80% husk and 20%sand. Then how much husk needs to be extracted in order to have 75% concentration of husk?

Answer 1

Total weight of mixture = 200lb

percentage of husk = 80%

amount of husk present in mixture

= 200×80/100

=160 lb

now, 75% of needed concentration

= 200 × 75/100

=150lb

difference = 160lb - 150lb

= 10lb

so 10lb of husk must be extracted to have 75% of concentration