Question

If 200 ml of sea water is mixed with 800 ml of fresh water, what is the density of the mixture?

Answer 1

Answer:

$M= V 1​ +V 2​ (V 1​ ×M 1​ )+(V 2​ ×M 2​ )​ M= 800 mL + 200 mL ( 800 mL × 0.5 mol/L)+( 200 mL × 1 mol/L)​ = 0.6 M$

Explanation:

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Answer 2

Explanation:

0.6 m

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