Question

If 2016 = 2^x 3^y 5^z 7^u where x,y,z,u are non negative integers, the value of x +y+2016z +3u is

Answer 1

Answer:

10

Step-by-step explanation:

2016= 2^x3^y5^z7^u

2^5x3^2x7x5^0=2^x3^y5^z7^u

Comparing both side we get -

x=5

y=2

z=0

u=1

Now,

x+y+2016z+3u

= 5+2+0+3x1

=5+2+0+3

=10

Answer 2

Answer:

10

Step-by-step explanation:

2016= 2^x3^y5^z7^u

2^5x3^2x7x5^0=2^x3^y5^z7^u

Comparing both side we get -

x=5

y=2

z=0

u=1

Now,

x+y+2016z+3u

= 5+2+0+3x1

=5+2+0+3

=10