Question

if 2019 degrees then what is the value of sin square x+ cos square x​

Answer 1

If 2019 degrees, then what is the value of  \sin$x^{2}$\ + \sin$x^{2}$\  = 1.

Step-by-step explanation:

Given, x = 2019°

∴ \sin$x^{2}$\ + \sin$x^{2}$\

= sin$2019^{2}$\ + \sin$2019^{2}$\

= 1 {∵ \sin{$x^{2}$} + \cos{$x^{2}$} = 1}

Hence, \sin$x^{2}$\ + \sin$x^{2}$\  = 1.