Question

If √2048=√2^x,√2187=√3^y and √3125 = √5^z then the value of x+y-z is?
(Step by step answer needed please!)

Answer 1

$\huge {\underline{\underline{ANSWER}}}}$

$\sqrt{2048} = { \sqrt{2} }^{x} \\ \\ \\ = > {2}^{11 \times \frac{1}{2} } = {2}^{x \times \frac{1}{2} } \\ \\ \\ x = 11 \\ \\ \\ \sqrt{2187} = { \sqrt{3} }^{y} \\ \\ \\ {3}^{8 \times \frac{1}{2} } = {3}^{y \times \frac{1}{2} } \\ \\ \\ y = 8 \\ \\ \\ \sqrt{3125} = { \sqrt{5} }^{z} \\ \\ \\ {5}^{5 \times \frac{1}{2} } = {5}^{z \times \frac{1}{2} } \\ \\ \\ z =5 \\ \\ \\ x + y - z = 11 + 8 - 5 \\ \\ \\ = 14$

Answer 2

Here is your answer

x=11

y=8

z=5

hence x+y-z = 11+8-5

which is equal to = 14