Question

If 20cm3 of 1.0M CaCl2 and 60.0cm3 of 0.20M CaCl2 are mixed, what will be the molarity of the final solution?

Answer 1

Answer:

molarity =0.4M

Explanation:

case 1

M =No. of moles/vol.of cacl2

1=no of moles/0.02

0.02 moles in 20 cm3 of 1.0Mcacl2

case 2

0.02=no of moles/0.06

0.012 moles in 60cm3 of 0.2M cacl2

Molarity =0.02+0.012/0.08

=0.032/0.08

=0.4M