If 20g NaOH and 36.5g HCl are added in 360g water then % by wt. HCl present in resulting mixture?
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36.5/416.5 *100 = 8.76% approx
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Explanation:
First we have to find the total mass of the new solution.
msolution=360 g H2O+20 g NaOH+36.5 g HCl
=416.5 g total
Then, we divide the mass of hydrochloric acid by the mass of the new solution and multiply by 100%.
% weight HCl=36.5g416.5g⋅100%≈8.76%
First we have to find the total mass of the new solution.
msolution=360 g H2O+20 g NaOH+36.5 g HCl
=416.5 g total
Then, we divide the mass of hydrochloric acid by the mass of the new solution and multiply by 100%.
% weight HCl=36.5g416.5g⋅100%≈8.76%
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