Question

If 20g of CaCO3 is treated with 20g of HCL, how many grams of CO2 will be produced along with CaCl2 and H20?

Answer 1

Generated mass of
$co _{2}$
during in the given reaction is 8.8 g.
Balanced reaction:  
$caco_{3} + 2hcl = > cacl _{2} + co _{2} + h _{2}o$
From the reaction,  
1 mole of calcium carbonate reacts with 2 moles of Hydrogen chloride and produce 1 mole of carbon dioxide.
Let’s calculate the moles of
$caco _{3}$
Molar mass of
$caco _{3}$
= 100 g/mol
Given mass of
$caco_{3}$
= 20 g
Moles of
$caco_{3} = \\ \frac{mass \: of \: caco _{3} }{molar \:mass \: of \: caco_{3} \: } \\ = \frac{20}{36.5} = 0.548 \: mol$
Therefore,
$caco _{3}$
is limiting reagent.
0.20 mol of  gives 0.20 mol of
$co _{2}$

Molar mass of
$co _{2}$
= 44 g/mol
Mass of
$co_{2} \: produced \: = 0.2 \times \frac{44g}{mol} = 8.8$
hope it helps you