IF 20g of CaCO3 is treated with 20g of HCl , How many grams of CO2 be produced given reaciton . CaCO3+HCl areeo CaCl2+H2O+CO2
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Answer:
amount of co2 =8.8 g
Explanation:
according to the equation ,
for 100 g of caco3⇒ 73 g of hcl is needed
here we have 20 g of caco3 and 20 g of hcl,so the limiting reagent is caco3...so product formed will be according to the amount of caco3,
thus for 100 g of caco3⇒ 44g of co2 will be produced
that is for 1 g of caco3⇒44/100 g of co2
so 20 g of caco3⇒ 44/100 × 20 of co2 formed
=8.8 g
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