If 20g of CaCO3 is treated with 20g of HCl.How many grams of CO2 can be produced according to the reaction?
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Number of moles in 20 grams CaCO₃ = 20/100 = 0.2 moles
Number of moles in 20 grams HCl = 20/36.5 = 0.54 moles
CaCO₃ + 2HCl -------------> CaCl₂ + CO₂ + H₂O
In the above equation 1mole of CaCO₃ reacts with 2moles of HCl to give 1mole of CO₂.
So, 0.2 moles of CaCO₃ reacts with 0.4moles of HCl to give 0.2moles of CO₂.
It simply means that after this reaction, the moles of HCl left (0.54-0.4 =0.13)
will not have any CaCO₃ left in the container for the reaction to happen.
So only 0.2moles of CO₂ will be formed.
Mass of 0.2moles of CO₂ = 0.2 x 44 = 8.8 grams
Number of moles in 20 grams HCl = 20/36.5 = 0.54 moles
CaCO₃ + 2HCl -------------> CaCl₂ + CO₂ + H₂O
In the above equation 1mole of CaCO₃ reacts with 2moles of HCl to give 1mole of CO₂.
So, 0.2 moles of CaCO₃ reacts with 0.4moles of HCl to give 0.2moles of CO₂.
It simply means that after this reaction, the moles of HCl left (0.54-0.4 =0.13)
will not have any CaCO₃ left in the container for the reaction to happen.
So only 0.2moles of CO₂ will be formed.
Mass of 0.2moles of CO₂ = 0.2 x 44 = 8.8 grams
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