If 20g of NAOH, ekxiynayrs,reacts with HCL WHAT FORM ? Give example waiting for answers
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If 20 g of NaOH reacts with 20g of HCl to produce NaCl and water, what is the reagent in excess and calculate the mass of NaCl produced during the reaction?
Balanced equation:
NaOH (aq) + HCl(aq) → NaCl (aq) + H2O(l)
1 mol NaOH reacts with 1 mol HCl to produce 1 mol NaCl
Check for limiting reactant
Molar mass NaOH = 40 g/mol
20 g NaOH =20 g / 40 g/mol = 0.5 mol
This will require 0.5 mol HCl
Molar mass HCl = 36.5 g/mol
20 g HCl = 20 g / 36.5 g = 0.548 mol HCl
The HCl is in excess - The NaOH is limiting
0. 5 mol NaOH will produce 0.5 mol NaCl
Molar mass NaCl = 58.5 g/mol
Mass of 0.5 mol NaOH = 0.5 mol * 58.5 g/mol = 29.25 g NaCl produced .
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