If 20g of the gas takes 50 sec for diffusion, then find the mass of a gas which takes 20 sec for diffusion let the molar mass of gas is 40gm
Answers
Answer:
Explanation:
CHEMISTRY
20 L of SO
2
diffuses through a porous partition in 60 seconds. Volume of O
2
diffuse under similar conconditionsin 30 seconds will be :
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ANSWER
The rate of diffusion is volume diffused per unit time and is inversely proportional to the square root of molar mass.
r
′
r
=
V
′
t
Vt
′
=
M
M
′
Here, r, V, t, and M are the rate of diffusion, the volume diffused, the time taken for diffusion and the molar mass of SO
2
and r', V', t' and M' are the rate of diffusion, the volume diffused, the time is taken for diffusion and the molar mass of O
2 respectively.
Substitute values in the above equation
V ×60 20×30
= 64 32
V =14.14 L.
Hence, a volume of O
2
diffused under similar conditions in 30 seconds will be 14.14 L.
So, the correct option is B