if 20gm of He are diffused in 5 sec calculated the mass of o2 diffused in 10 sec.
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2
Answer:
Given,
Time taken for oxygen diffusion=10 sec
Also pressure,volume,temperature is constant.
Molar mass of oxygen=32g/mole
Molar mass of sulphur dioxide=64g/mole
According to graham's law of diffusion/effusion
r∝
M
1
r=rate of diffusion
M=molar mass
r
SO
2
r
O
2
=
M
O
2
M
SO
2
since,
r=V/T,r∝
t
1
t
O
2
t
SO
2
=
M
O
2
M
SO
2
10
t
SO
2
=
32
64
t
SO
2
=14.14
Explanation:
hope it helps you
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0
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