Question

if 20ml,2M H2SO4 is diluted to1 litre.normality of the resulting solution

Answer 1

dear
we know m1v1=m2v2
given:m1=2 and v1=20ml v2= 1 lit
But 1 lit =1000ml
now,according to the formula
m1v1=m2v2
m1,v1,v2 is given then m2 will b
m2=m1v1÷v2
=2×20÷1000
=40÷1000=0.04
now,N=molarity×v-factor
=0.04×2
=0.08
Which is the answer

Answer 2

Answer: Normality of the resulting solution is 0.080 N.

Explanation:

$M_1=2M,V_2=20 mL=0.020 L$(1L = 1000mL)

$M_2=?,V_2=1 L$

$M_1\times V_1=M_2\times V_2$

$M_2=\frac{M_1\times V_1}{V_2}=\frac{2 M\times 0.020 L}{1L}=0.040 M$

Normality of the 1 L solution of $H_2SO_4$ = n × Molarity

n = acidity of the acidic solution that is number of ionisable $H^+$ ions in molecular formula of an acid.

$Normality=2\times 0.040=0.080 N$

Normality of the resulting solution is 0.080 N.