Question

If 20ml of 0.4n, naoh solution completely neutralises 40ml of a dibasic acid. the molarity of

Answer 1

the molarty of what
..........

Answer 2

Answer: The molarity of the given acid is 0.1M.

Explanation:

Relation between normality and molarity is given by the equation:

N = nM

where, N = Normality

n = acidity for bases and basicity for acids.

M = molarity

As, NaOH is a monoacidic base, so, n = 1.

Molarity of NaOh will be = 0.4M

For a neutralization reaction, to calculate the molarity, we use the formula:

$n_1M_1V_1=n_2M_2V_2$

$n_1,M_1\text{ and }V_1$ = acidity, molarity and volume of NaOH solution

$n_2,M_2\text{ and }V_2$ = basicity, molarity and volume of dibasic acid.

$n_1=1\\M_1=0.4M\\V_1=20mL\\n_2=2\\M_2=?M\\V_2=40mL$

Putting values in above equation, we get:

$1\times 0.4\times 20=2\times M_2\times 40\\\\M_2=0.1M$

Hence, the molarity of the given acid is 0.1M.