Question

if 20mll of H2 and 10ml of O2 react to form water how much water formed​

Answer 1

Answer:

see this attachment Hope it helps uh mate

Answer 2

$\red{\huge{\underline{\underline{Answer:-}}}}$

Given :

20 ml H2 and 10ml O2 react to form water

To find :

Amount of water formed = ?

Solution:

2H2 + O2 ------> 2H2O

$Mole \: of \: H2 \: = \dfrac{volume}{22.4}$

$\\ = \frac{20}{22.4} \\ \\ = 0.89 \\ \\ mole \: of \: H2 \: is \: 0.89$

$\\ Mole of O2 = \frac{volume}{22.4} \\ \\ = \frac{10}{22.4} \\ \\ = 0.44 \: mole$

$Limiting \: reagent \: = \frac{mole \:}{stoichiometry}$

$\\ for \: o2 = \dfrac{0.44}{1} \\ = 0.44$

$\\ for \: h2 = \: \frac{0.89}{2} \\ = 0.44$

Stoichiometric coefficient is 1 for O2, 2 for H2

Here, For oxygen and hydrogen both are limiting reagent so let's consider any one

1 mole oxygen gives 2 mole H2O

0.44 mole oxygen gives 2×0.44/1 = 0.88 mole H2O

If we need in volume,

1 ml oxygen gives 2ml H2O

10 ml oxygen gives 10×2/1 = 20 ml H2O

Therefore, 20ml Or 0.88 mole H20 is formed

Additional points:

1. In 2C + 2O2 ----> 2CO2. Here, stoichiometric coefficient of CO2 is 2, C is 2 and O2 is 2
2. Mole = Mass/ Molar mass
3. Mole = Volume/ 22.4
4. Mole = Number of molecules/ 6.02 × 10^23
5. Try to solve more such problems for good hold on it