Question

If 21,168=x^4*y^3*z^2,then find(x+y+z)(y+z/x+y),where x , y, and z are positive integers. For understanding question better pls check out the photo. Question no 35

Answer 1

Answer:

144

Step-by-step explanation:

$21168 = {x}^{4} \times { y }^{3} \times {z}^{2} \\ 21168 = {2}^{4} \times {3}^{3} \times {7}^{2} \\ x = 2 \: \: \: \: y = 3 \: \: \: \: z = 7$

${(x + y + z)}^{ (\frac{y + z}{x + y}) } \\ = {(2 + 3 + 7)}^{ \frac{3 + 7}{2 + 3} } \\ = {12}^{ \frac{10}{5} } \\ = {12}^{2} \\ = 144$

hope you get your answer